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How many 5 digit numbers can be formed by using 3, 4, 5, 6, 7, if 6 is necessarily taken at hundred's place.............

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How many 5 digit numbers can be formed by using 3, 4, 5, 6, 7, if 6 is necessarily taken at hundred's place and 4 is not allowed at unit's place?
Note : Repetition of numbers is not allowed.

posted 6 days ago by Aastha Joshi

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1 Answer

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6 is necessarily taken at hundred's place and 4 is not allowed at unit's place,
hence number of options = 3*2*1*1*3 = 18

answer 6 days ago by Hanifa Mammadov



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