Total digit =8
we contain only five digit at a time so total ways,and not any digit repeated
By permutation 8P5=8!/(8-5)!
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 0, which are divisible by 5 and none of the digits is repeated?
If repetition of numbers is not allowed then how many numbers of five digits can be formed by using 1,2,3,4,5.
If 4 is necessarily taken at hundred's place and 2 is not allowed at unit's place