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How many numbers can be formed from 1, 2, 3, 4, 5 (without repetition), when the digit at the unit's place must.........

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How many numbers can be formed from 1, 2, 3, 4, 5 (without repetition), when the digit at the units place must be greater than that in the ten's place?

posted Sep 3 by Nikita Sehgal

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1 Answer

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1 cant be in units place


If 2 in units place 1 has to be in tens place
We can have 3×2×1 = 6 possible numbers here


If 3 is in units place than we can either 1 or 2 at tens place
Then we have 3×2×1×2 for the rest of the slots = 12 numbers


If 4 at units place we can have 1, 2 & 3 at tens
For 1, 2 & 3 we have 3×2×1×3 = 18 numbers


Similarly for 5 at units place we have 3×2×1×4 = 24 numbers


Total such numbers = 6 + 12 + 18 + 24 = 60 numbers.

answer Sep 4 by Tejas Naik



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