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How many 3 digit numbers can be formed from digits 2, 3, 5, 6, 7 & 0, which are divisible by 5 and none is repeated?

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How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 0, which are divisible by 5 and none of the digits is repeated?

posted Dec 28, 2016 by anonymous

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1 Answer

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Looks 36. Ending with 0 we have to select two others from 5 which means 5P2=20. Similarly ending with 5 we have another 20 of which 4 starting with zero must be excluded. Hence 20+16=36

answer Dec 28, 2016 by Kewal Panesar
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