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Present ages of A,B and C are in ratio 4:5:6. Eight years ago sum of their ages was 66. Sum of present age of A and C?

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The present ages of A,B and C are in proportions 4:5:6. Eight years ago, the sum of their ages was 66. What is the sum of present age of A and C?

Solve this without paper and pen?

posted Feb 28, 2017 by anonymous

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1 Answer

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60
.
Eight years ago their combined age was 66. Now their combined age is 66 + 3*8 = 66 + 24 = 90
Their current age is 4*x, 5*x and 6*x, which combines to 90.
Thus, (4+5+6)*x = 90 -> 15*x = 90 -> x = 6
The current ages are: 4*6 = 24; 5*6 = 30 and 6*6 = 36
A + C = 24 + 36 = 60.

answer Feb 28, 2017 by Jcm



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