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The age of a father 10 years ago was thrice the age of his son . Ten years hence, the father's age will be twice that of his son. What is the ratio of their present ages?
Father:Son > 7:3
Say father's age= X, Son's Age = Y
10 years ago, X-10 = 3*(y-10) >> 3Y=X+20
10 years from now, X+10 = 2*(Y+10) >> 2Y=X-10
Solve and get, Y=30, X=70.
Present age is 1:3
Ratio of Son:Father age 1:2
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The present ages of A,B and C are in proportions 4:5:6. Eight years ago, the sum of their ages was 66. What is the sum of present age of A and C?
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