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The age of a father 10 years ago was thrice the age of his son . Ten years hence, the father's age will be twice that of his son. What is the ratio of their present ages?
Father:Son > 7:3
Say father's age= X, Son's Age = Y
10 years ago, X-10 = 3*(y-10) >> 3Y=X+20
10 years from now, X+10 = 2*(Y+10) >> 2Y=X-10
Solve and get, Y=30, X=70.
Present age is 1:3
Ratio of Son:Father age 1:2
The ratio of present ages of Ram and Shyam is 4:3. If 10 years ago Ram was half of Shyam in age, what is the sum of their present ages?
The sum of the present ages of a father and his son is 60 years. Six year ago, father's age was five times the age of the son. After 6 years, what will be son's age?
The present ages of A,B and C are in proportions 4:5:6. Eight years ago, the sum of their ages was 66. What is the sum of present age of A and C?
Solve this without paper and pen?
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56.
Find their present ages (in years).
The age difference between two brothers is 6 years.
After 6 years the ratio between the age is 8 : 5.
What would be the sum of their present ages?
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