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The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56.
Find their present ages (in years).
then present age=16,28 and36
(4x-8) + (7x-8) + (9x-8) = 56
4x + 7x + 9x - 24 = 56
20x = 56 + 24 = 80
x = 80 / 20 = 4
x = 4,
Proportion is 4 : 7 : 9.
So, their present ages= 16 , 28 and 36
The present ages of A,B and C are in proportions 3:4:5.
Six years ago, the sum of their ages was 54.
What is the product of their ages?
The ratio of present ages of Ram and Shyam is 4:3. If 10 years ago Ram was half of Shyam in age, what is the sum of their present ages?
The present ages of A,B and C are in proportions 4:5:6. Eight years ago, the sum of their ages was 66. What is the sum of present age of A and C?
Solve this without paper and pen?
The age of a father 10 years ago was thrice the age of his son . Ten years hence, the father's age will be twice that of his son. What is the ratio of their present ages?
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?
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