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The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56.
Find their present ages (in years).
then present age=16,28 and36
(4x-8) + (7x-8) + (9x-8) = 56
4x + 7x + 9x - 24 = 56
20x = 56 + 24 = 80
x = 80 / 20 = 4
x = 4,
Proportion is 4 : 7 : 9.
So, their present ages= 16 , 28 and 36
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Solve this without paper and pen?
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