### Given digit are 2,3,4,5,6,7,8,9

**Total digit =8**

we contain only five digit at a time so total ways,and not any digit repeated

By permutation 8P5=8!/(8-5)!

=6720

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How many five digit numbers can be formed from the digits, 2, 3, 4, 5, 6, 7, 8 and 9 with no digit repeated?

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