There should 4C3 = 4 such numbers where the numbers chosen for the 3 digit numbers aren't repeated.
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 0, which are divisible by 5 and none of the digits is repeated?
If repetition of numbers is not allowed then how many numbers of five digits can be formed by using 1,2,3,4,5.
If 4 is necessarily taken at hundred's place and 2 is not allowed at unit's place
A five-digit number is formed using digits 1,3,5,8 and 9 without repeating any one of them.
What is the sum of all such possible numbers?