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a+b = 11
(a+b)^2 = a^2+b^2+2ab
Now lets look at
(a+b)(a^2+b^2) = a^3+ab(a+b)+b^3
11*99 = a^3+b^3+11*11
a^3+b^3 = 968
Answer is 968
answer is 1210
The sum of 3 single digit numbers is 15 less than their product . If we subtract 2 from first given number then sum of these numbers will become 7 more than their product. Then what will be the product of given 3 numbers?
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