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The sum of 3 single digit numbers is 15 less than their product . If we subtract 2 from first given number then sum of these numbers will become 7 more than their product. Then what will be the product of given 3 numbers?

The numbers are 2,3,4 where 2 is the first number

let the three numbers be x,y,z then,x+y+z=x*y*z - 15 & (x-2)+y+z=(x-2)*y*z + 7 solving these we will get y*z=12 possiblities are {1,12} , {2,6} , {3,4} taking these {3,4} is satisfying the conditions giving x=2 so x*y*z=2*12=24