Remember

Connect to us

If there exists only one ordered pair of natural number (x, y) : x^3 - y^3 = xy + 61 then find xy?

+1 vote

177 views

posted Jun 17, 2019 by anonymous

Share this puzzle

Your comment on this post:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Anti-spam verification:

To avoid this verification in future, please log in or register.

0 votes

x=6, y=5, xy=30

answer Jun 17, 2019 by Hanifa Mammadov

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Anti-spam verification:

To avoid this verification in future, please log in or register.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

Anti-spam verification:

To avoid this verification in future, please log in or register.

Similar Puzzles

0 votes

If X - Y = XY = 10 then find the value of X^4 + Y^4

0 votes

0 votes

If x + y = 7 and x^3 + y^3 = 133 then xy=??

If
x + y = 7 &
x^3 + y^3 = 133
Then
xy=??

Where x,y both are real numbers.

0 votes

+1 vote

If
x, y, z are 3 non zero positive integers such that x+y+z = 8 and xy+yz+zx = 20,
then
What would be minimum possible value of x*y^2*z^2

...