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x, y, z are 3 nonzero positive int such that x+y+z = 8 and xy+yz+zx = 20, then what will be minimum value of x*y^2*z^2

+1 vote
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If
x, y, z are 3 non zero positive integers such that x+y+z = 8 and xy+yz+zx = 20,
then
What would be minimum possible value of x*y^2*z^2

posted Mar 20, 2015 by anonymous

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5 Answers

+3 votes

Values are 4,2,2
So answer is 64

answer Mar 20, 2015 by Jaspalsingh Parmar
values are 6,1,2
So answer is 24
6+1+2 = 9 not 8, so answer 64 is correct i think
0 votes

Solving we got
X*y^2*z^2 = X(x^2-8x+20)
Since X has a positive value and we have to get minimum then putting X=1
We get
169
So 169 is the answer

answer May 12, 2016 by Sachite Anand
0 votes

ans is 64, for minimum value, x,y& z will be 4,2 &2,

answer May 12, 2016 by Hasan Raza
0 votes

4, 2, 2
answer 64

answer Aug 23, 2016 by Danny Shterman
0 votes

2, 3+sqr(5), 3-sqr(5)
The answer is 32

answer Aug 23, 2016 by anonymous



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