   # x, y, z are 3 nonzero positive int such that x+y+z = 8 and xy+yz+zx = 20, then what will be minimum value of x*y^2*z^2

+1 vote
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If
x, y, z are 3 non zero positive integers such that x+y+z = 8 and xy+yz+zx = 20,
then
What would be minimum possible value of x*y^2*z^2 posted Mar 20, 2015
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## 5 Answers

+3 votes

Values are 4,2,2
So answer is 64 answer Mar 20, 2015
values are 6,1,2
So answer is 24
6+1+2 = 9 not 8, so answer 64 is correct i think
0 votes

Solving we got
X*y^2*z^2 = X(x^2-8x+20)
Since X has a positive value and we have to get minimum then putting X=1
We get
169
So 169 is the answer answer May 12, 2016
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ans is 64, for minimum value, x,y& z will be 4,2 &2, answer May 12, 2016
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4, 2, 2
answer 64 answer Aug 23, 2016
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2, 3+sqr(5), 3-sqr(5)
The answer is 32 answer Aug 23, 2016 by anonymous

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