For 8 people, the logic is :

(Is my logic OK ?)

Out of 100 people,

-25 did not have PC,

-32 did not have DW

-15 did not have fridge

-20 did not have VC

Hence number of people having all the four are

But is there a loophole in above.

Numbers can not be added as some could be common, but not have 2 or 3 or any of the items.

If you go by probability theory then the answer is 34.68%