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if a,b,c,d are positive real numbers and a^2+b^2=c^2+d^2=2 then what is the max value of ac+bd?

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if a,b,c,d are positive real numbers and a^2+b^2=c^2+d^2=2 then what is the max value of ac+bd?
posted Nov 9, 2017 by anonymous

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1 Answer

0 votes

Answer:

16

How:

a^2+b^2=c^2+d^2=2
From this we can say, a=b=c=d=±1
So, ac+bd = (±1)(±1)+(±1)(±1) = 1+1 = 2

answer Dec 29, 2017 by Yasin Hossain Siinan
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