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if a*b=1 and a and b re +ve (a+b) >2(get by squaring a+b). minimum should be 5 for a+b+c+d+e when all are 1

a*b=1 and a and b re +ve (a+b) >2(get by squaring a+b). minimum should be 5 for a+b+c+d+e when all are 1

let us start with a*b=1 then b=1/a a+b=a+(1/a) differentiate f(a)=a+(1/a) f '(a)=a-(1/a*a) equate to zero a=1,-1 since a is positive a=1, b=1. differentiate second time f"(a)=2/(a*a*a) at a=1 it is positive hence minima generalize a=b=c=d=e=1

If abcde=1 (where a,b,c,d and e are all positive real numbers) then what is the minimum value of a+b+c+d+e?

Give positive numbers a, b and c are such that ab + bc + ca + abc = 4, What is the value of 1/a+2 + 1/b+2 + 1/c+2 = ?

Find the value of a+b+c+d If a,b,c,d are positive numbers of algebraic sequence and a,b,c+4,d+13 are positive numbers of a geometric sequence