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if a*b=1 and a and b re +ve (a+b) >2(get by squaring a+b). minimum should be 5 for a+b+c+d+e when all are 1
a*b=1 and a and b re +ve (a+b) >2(get by squaring a+b).
minimum should be 5 for a+b+c+d+e when all are 1
let us start with a*b=1
equate to zero
a=1,-1 since a is positive a=1, b=1.
differentiate second time
at a=1 it is positive hence minima
abcde=1 (where a,b,c,d and e are all positive real numbers)
what is the minimum value of a+b+c+d+e?
Give positive numbers a, b and c are such that
ab + bc + ca + abc = 4,
What is the value of
1/a+2 + 1/b+2 + 1/c+2 = ?
Find the value of a+b+c+d
If a,b,c,d are positive numbers of algebraic sequence and
a,b,c+4,d+13 are positive numbers of a geometric sequence
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