Cube root of 8 = 2

Therefore (1+a) = 2 = (1+b) = (1+c) {any other values of a, b & c that yields 8 as the answer will have at least 1 negative variable}

a = 1 = b = c

Therefore max of a×b×c = 1 in the domain of (1+a)(1+b)(1+c) = 8

+1 vote

If a,b and c are positive real numbers, such that (1+a)(1+b)(1+c) = 8 then the maximum value of a.b.c

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