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A is 2 years older than B who is thrice as old as C. Total of ages of A, B and C is 51. What is product of their ages?

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A is 2 years older than B who is thrice as old as C. Total of ages of A, B and C is 51. What is product of their ages?
posted Jul 13, 2017 by anonymous

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1 Answer

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A = B+2
B = 3C
A + B + C = 51
A + (A-2) + ((A-2)/3) = 51
2A + A/3 = 51 + 2 + (2/3)
7A = 53*3 + 2
A = 161/7 = 23.

Therefore A x B x C = 23 x 21 x 7 = 3381

answer Jul 13, 2017 by Tejas Naik



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