A is 4 year older than B ->A=B+4.......1

who s twice as old as C ->B=2C........2

Total of the ages of A, B and C is 44-> A+B+C=44------------3

substitute A,B value

B+4+2C+C=44

B+3C=40...........4

take 2nd and 4th equation

B+3C=40

### B-2C=0

### C= 8

A=20,B=16,C=8

product of their ages ->A*B*C=2560