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Calculate without substitution 1 + a + 2b + 3c + 2ab + 3ac + 6bc + 6abc if a=999, b=666 and c=333

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Calculate without substitution 1 + a + 2b + 3c + 2ab + 3ac + 6bc + 6abc if a=999, b=666 and c=333
posted Oct 10, 2015 by anonymous

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1 Answer

0 votes

Factors are
(1+a)(1+2b)(1+3c)
=> (1+999)(1+2*666)(1+3*333)
=> 1000*1333*1000
=> 1333000000

Answer: 1333000000

answer Oct 13, 2015 by Salil Agrawal
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