Factors are

(1+a)(1+2b)(1+3c)

=> (1+999)(1+2*666)(1+3*333)

=> 1000*1333*1000

=> **************

Answer: **********

+1 vote

Calculate without substitution 1 + a + 2b + 3c + 2ab + 3ac + 6bc + 6abc if a=999, b=666 and c=333

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