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## Homework Statement

a 300 kg crate is on a rough surface inclined at 30 degrees. A constant force P=2400 N is applied horizontally to the crate. The force pushes the crate a distance of 3.0 m up the incline, in a time interval of 9.0 s, and the velocity changes from v1=0.7 m/s and v2=2.9 m/s. What is the work done by the weight?

## Homework Equations

WD=F.d

## The Attempt at a Solution

i have found the parallel components:

Fnet=Psin(theta) -mgsin(theta)

Psin(theta)-mgsin(theta)=ma

and the perpendicular components:

Fnet=Fn-mg

Fn=mg

I'm not 100% sure any of this is correct, and now I don't know where to go with it