I am a four digit number that is the same when my digits are written backwards. ................... What number am i ?

+1 vote
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I am a four digit number that is the same when my digits are written backwards. The sum of my outside digits is 6 times the sum of my two middle digits . What number am i ?

posted Jul 28, 2015

+1 vote

6116 is the number.

+1 vote

I am a four digit number that is the same when my digits are written backwards.

Implies first and last digit is same and 2nd and 3rd digit is same.

let first digit be x ,hence last digit will also x
Let 2nd digit=3rd digit=y

The sum of my outside digits is 6 times the sum of my two middle digits
hence,2x=12y
x=6y
if, y=1,than x=6
so number will be 6116

if y=2,then x=12 which is not possible.

Hence the four digit number is 6116

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–1 vote

I am thinking of a five digit number such that:
First and last digits are same, their submission is an even number and multiplication is an odd number and is equal to the fourth number. Subtract five from it and we obtain the second number. Then divide into exact half nd we get 3rd number.

What number I am thinking of?