   I am thinking of a five digit number such that: First and last digits are same.............What number I am thinking of?

–1 vote
416 views

I am thinking of a five digit number such that:
First and last digits are same, their submission is an even number and multiplication is an odd number and is equal to the fourth number. Subtract five from it and we obtain the second number. Then divide into exact half nd we get 3rd number.

What number I am thinking of? posted Dec 8, 2015

1st digit =3
5th digit=3
4th digit =3*3=9
2nd digit =9-5=4
3rd digit =4/2=2

so ans is 34293 answer Dec 8, 2015

Similar Puzzles
+1 vote

I'm a 5 digit number,
the first and last digits are the same and add up to an even number.
Multiply that number by its self and the number is under 10 and odd.
That will be the fourth number.
Subtract five from it and it will be the second number.
Divide it in half and that is my third number.

What am I?

+1 vote

I am a four digit number that is the same when my digits are written backwards. The sum of my outside digits is 6 times the sum of my two middle digits . What number am i ?

+1 vote

A 9-digit number has a property that the first 'n' digits are divisible by 'n'. There is no '0' in the number and all the digits in the number are distinct. What is the number?

Its a 4 digit Car Plate Number: KL45 - _ _ _ _
1. Last digit is double of First digit.
2. Second digit & Third digits are the same.
3. Last two digit is the double of the First Two digit.

So whats the Car plate No.
KL45 - _ _ _ _