1) add water in 3L
3) again fill 3L
4) tranfer 3L to 5L ...now 5L is full .and in 3L its 1L remaining
5) throw 5L water and put 1L back into 5L
6) again fill 3L and tranfer to 5L ..now its 4L in 5l
This was the question of two buckets of 3 and 5 litres each. Now measure four litre. I had given 2 solutions but still he wanted 3 solution.
1st soln: fill 3 litre and then interchange in various ways to get 4 litre.
2nd soln: fill 5 litre and then interchange in various ways.
you are given four different jars of 2 litres, 4 litres, 6 litres and 8 litres respectively with an unlimited water supply.
Then you are asked to measure exactly 5 liters of water using them.
How will you do it?
5 litres of HCL is added to 15 litre of a solution containing 40% of DI water.
What is the percentage of DI water in the new mixture?