# The figure shows an isosceles triangle with AB = BC. The line DE cuts AC extended at F. If AD=5, CE=3 and EF=8 find DE.

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The figure shows an isosceles triangle with AB = BC. The line DE cuts AC extended at F. If AD=5, CE=3 and EF=8 find DE.

posted Jun 18, 2015

What are your "sine rules"? Where are the right angles?
Dear teuxe , sine rules applied here are
In a triangle ABC with sides a,b,c and its corresponding opposite angles A,B,C
{a/Sin(A)}={b/Sin(B)}={c/Sin(C)}  , holds for for any triangle , there are no right angles here ..

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