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In triangle ABC, D and E are points on sides AB and AC respectively such that AD × EC = AE × DB. Prove that DE || BC?

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In triangle ABC, D and E are points on sides AB and AC respectively such that AD × EC = AE × DB. Prove that DE || BC?
posted May 28, 2017 by anonymous

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2 Answers

0 votes

AD*EC=AE*DB gives
AD/DB=AE/EC ADD 1 BOTH SIDES
AD/AB=AE/AC GIVES TRIANGLES ADE AND ABC SIMILAR TRIANGLES
POSSIBLE ONLY IS IF DE IS PARALLEL TO BC

answer Jun 13, 2017 by Kewal Panesar
–1 vote

It will be proved by BPT theorem

answer May 28, 2017 by Vanshika Sharma
Can you help with the detail theorem?



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