# In triangle ABC, D and E are points on sides AB and AC respectively such that AD × EC = AE × DB. Prove that DE || BC?

449 views
In triangle ABC, D and E are points on sides AB and AC respectively such that AD × EC = AE × DB. Prove that DE || BC?
posted May 28, 2017

POSSIBLE ONLY IS IF DE IS PARALLEL TO BC

–1 vote

It will be proved by BPT theorem

Can you help with the detail theorem?

Similar Puzzles
+1 vote

In a Right angle triangle ABC

AB=3,AC=4 & BC=5

at BC,E is middle point and D is altitude AD

Find distance DE=?

it is not a difficult question everyone who know maths ...
Can YOU solve it easily ...... solve it in one line...........or in second..........?

–1 vote

In a triangle ABC, Angle A=84, B=78. Points D and E are taken on the sides AB and CB so that angle ACD=48 and CAE=63.
What is the measure (in degrees) of angle CDE?

The figure shows an isosceles triangle with AB = BC. The line DE cuts AC extended at F. If AD=5, CE=3 and EF=8 find DE.

Triangle ABC has sides AB = 8, BC = 7, and AC = 9.
The segments AB and AC are extended and a circle O is constructed exterior to the triangle and is tangent to BC at D and the extended lines through AC and AB at N and M, as shown.
What is the radius of circle O?