If a bamboo 32 meters high is broken by wind so that the tip meets the ground at a point 16 meters far from the base, at what height above the ground was it broken?
Using Pythagoras gives us bc^2 + 16^2 = ac^2.
bc + ac = 32, therefore bc^2 + 16^2 = (32-bc)^2 = 1024 - 64*bc + bc^2
=> 768 = 64* bc => bc = 12
Ans is 12
Let height above ground be X
So, X^2+16^2 =(32-X)^2
By solving we get X=12
A man 180 cm tall stands 4.5 meter in front of a large vertical plane mirror then what is the angle subtended at the eye by his image in the plane mirror?
At a particular time the shadow of a men of 170 cm height is 204 cm on the ground and at the same time and on the same ground the shadow of a pole is 600 cm. Find the height of the pole?
From a point P on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, Then what is the the distance of point P from the foot of the tower.
Two poles of height 12 m. and 4 m. are situated in such a way that the sun rays through the top of a pole also passes through the top of other. What is the distance between the poles?
It is given that the sun rays make an angle of 45 degree with the horizon