2x + 3y = (39 - 6xy)/5

Now by first making 39 - 6xy a multiple of 5 , we get if 39-6xy=30 , or 6xy=9 we get xy=3/2 or 2x+ 3y=6 (x=3/2 , y=1) and rest all cases we are getting either x,y imaginary or 2x+ 3y >6

so minimun value is 6

+1 vote

If 6xy + 10x +15y = 39 then find the minimum value of 2x+3y (x, y are positive and real)?

...