# Four digit num has all non zero different even digit, what is the probability of first three digits in increasing order?

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Four digit num has all non zero different even digit, what is the probability of first three digits in increasing order?
posted May 6, 2015

Numbers have first 3 digits in increasing order
2468
2486
2684
4682

how probability can be more then 1
So may be the probability is 4/4! or 1/6 :)

Possible event of formation of 4 digits numbers by rearranging the digits 2, 4, 6, 8 is...
4! = 4×3×2×1 = 24
But, the numbers having first 3 digits in increasing order are, 2468, 2684, 4682, 2486
Therefore, probability will be...
4÷24 = 1/6

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