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A man throws three dices simultaneously..........What is the probability of getting three numbers whose product is even?

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A man throws three dices simultaneously on the floor.
What is the probability of getting three numbers whose product is even?

posted Oct 1 by Yogeshwar Thakur

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2 Answers

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There are a total of eight possible events here and all but one are in the favour of the required event (Odd*Odd*Odd = Odd)
Therefore the required probability = 7/8.

answer Oct 2 by Tejas Naik
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1- 1/2*1/2*1/2=7/8

answer Oct 2 by Hanifa Mammadov
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