First no. Is 9
And another 4
9+ 1/4 = 37/4
So sum of integers is 9+4=13
9+1/4 = 37/4
So the numbers are 9 and 4
Let a be a single-digit positive integer.
Let n be another positive integer that adjusts itself so that the unit's place digits of n and an + 1 are the same.
Find the sum of all possible values of a.
An integer x is selected in such a way that
x + x^(1/2) + x^(1/4) = 276
Then what would be the sum of all digits of the number y where
y = 100000 x^(1/4) + 1000 x^(1/2) + x