top button
Flag Notify
    Connect to us
      Facebook Login
      Site Registration Why to Join

    Get Free Puzzle Updates

Facebook Login
Site Registration

If x is an integer where x + x^(1/2) + x^(1/4) = 276 Then what would be the sum of all digits of the number y

+1 vote
152 views

An integer x is selected in such a way that

x + x^(1/2) + x^(1/4) = 276

Then what would be the sum of all digits of the number y where

y = 100000 x^(1/4) + 1000 x^(1/2) + x 
posted Feb 21, 2015 by Tapesh Kulkarni

Share this puzzle
Facebook Share Button Twitter Share Button LinkedIn Share Button

2 Answers

+5 votes
 
Best answer

X = 256
So
Y=400000+16000+256=416256
So sum of digits is 24

answer Feb 22, 2015 by Jaspalsingh Parmar
+1 vote

X = 256
given
y = 100000 x^(1/4) + 1000 x^(1/2) + x
then
Y=400000+16000+256=416256
So sum of digits = 24

answer Jan 31, 2016 by Mahendra Kumar Patel



Similar Puzzles
+2 votes

x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be

0 votes

If x, (x^3+1) and x^4 are in arithmetic progression,then what will be possible sum of 3 terms of arithmetic progression?
( given that x is real number )

Contact Us
+91 9880187415
sales@queryhome.net
support@queryhome.net
#280, 3rd floor, 5th Main
6th Sector, HSR Layout
Bangalore-560102
Karnataka INDIA.
QUERY HOME
...