Which Indian cricketer is known as "Brown Bradman"?

Which of the countries has had a prime minister whose name featured the name of his country?

Which of the gulf city was a dependency of Bombay Presidency under British rule for almost a century?

Which of the following Pair are not parent and child who have both won the Nobel prize?

Which singer was originally named Eileen Angelina Yeoward?

Which of these scientist was inspired to make its famous discovery in a sea voyage in 1921?

Which is the only talkie film directed by Dada Saheb Phalke?

Which company started by Europeans in Calcutta in 1818 was the first modern life insurance company established in India?

Which Shakespeare play was translated by the Bhartendu Harishchandra with the title Durlabh Bandhu, published in 1880?

Which Indian Cricketer is known as Hitman by the media?

If x, (x^3+1) and x^4 are in arithmetic progression,then what will be possible sum of 3 terms of arithmetic progression? ( given that x is real number )

Since the terms are in A.P

we have 2*(x^3 + 1) = x + x^4;; solving we get ;; (x-2)*(x+1) = 0

so we get values of x= 2 or -1 Hence possible sums of three terms will be

for x=2 will be { 2+9+16 ) = 27 for x= -1 will be {-1 + 0 + 1 } = 0

1) 1/2 2) 1 3) 3/2 4) 2 5) 5/2 6) 5/3 7) 5/4 8) 7/6 9) 6/13 10) 3/16

First and last term of a geometric progression are 3 and 96. If the sum of all these terms is 189, then find the number of terms in this progression.

An integer x is selected in such a way that

x + x^(1/2) + x^(1/4) = 276

Then what would be the sum of all digits of the number y where

y = 100000 x^(1/4) + 1000 x^(1/2) + x

x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be