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Find the value k such that: (22 * k) # (k * 33) = 27

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Let the operations '#' and '*' be defined as follows:

a * b = 1/a + 1/b
a # b = (a + b)/(a - b)

Find the value k such that: (22 * k) # (k * 33) = 27

posted Oct 14, 2014 by anonymous

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1 Answer

+1 vote

(k*22)=(22+k)/22k,
(k*33)=(33+k)/33k,
(k*22)#(k+33)=(132+5k)/k=27.
So, 132+5k=27k,
27k-5k=132,
22k=132, k=6

answer Oct 14, 2014 by Vrije Mani Upadhyay
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