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Find largest possible value of N, such that N! can be expressed as the product of (N-4) consecutive positive integers?

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Find the largest possible value of positive integer N, such that N! can be expressed as the product of (N-4) consecutive positive integers?

posted May 9, 2017 by anonymous

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1 Answer

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119


Largest positive integer n for which n! can be expressed as the product of n-a consecutive positive integers is (a+1)! - 1.
Proof - let the largest of the n-a consecutive positive integers be k. Clearly k cannot be less than or equal to n, else the product of n-a consecutive positive integers will be less than n!
Now, observe that for n to be maximum the smallest number (or starting number) of the n-a consecutive positive integers must be minimum, implying that k needs to be minimum. But the least k > n is n+1.

So the n-a consecutive positive integers are a+2, a+3, … n+1

So we have
(n+1)!/(a+1)! = n! => n+1 = (a+1)! => n = (a+1)! -1
for a=4 we have n= 5!-1=119

answer Jan 6, 2019 by Hanifa Mammadov



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