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The sum of squares of three successive integers is 26510. What is the sum of these integers?
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The sum of squares of three successive integers is 26510. What is the sum of these integers?
mathematical
posted
Mar 3, 2020
by
Varuna Magar
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1 Answer
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(x-1)^2+x^2+(x+1)^2=26510 --> x=94
(x-1)+x+(x+1)=94*3=
282
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Mar 3, 2020
by
Hanifa Mammadov
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