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The sum of squares of three successive integers is 6629. What is the sum of these integers?
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The sum of squares of three successive integers is 6629. What is the sum of these integers?
mathematical
posted
Jan 22, 2020
by
Rahul Vaidya
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1 Answer
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141
(x-1)^2+x^2+(x+1)^2=6629 --> x=47
(x-1)+x+(x+1)=47*3=
141
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Jan 22, 2020
by
Hanifa Mammadov
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