x^5 - 8x^4 + 2x^3 - 16x^2 + x - 8 = 0

x^5+2x^3+x -(8x^4+16x^2+8)=0

(x^2+1)^2*(x-8)=0

There is only one rational root --> x=8

So sin (π/8)= **0.************

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Let y be the rational root of x^5 - 8x^4 + 2x^3 - 16x^2 + x - 8 = 0. Find sin ( π / y ).

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