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When x^9 - x is factorized as completely, how many factors are there?

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When x^9 - x is factorized as completely as possible into polynomials and monomials with integral coefficients, how many factors are there?

posted Aug 14 by anonymous

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1 Answer

+1 vote

x^9-x=x(x^8-1)=x(x^4+1)(x^4-1)=x(x^4+1)(x^2+1)(x^2-1)=x(x^4+1)(x^2+1)(x+1)(x-1)--> 5 factors

answer Aug 15 by Hanifa Mammadov
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