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Modification of the Default APN
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Aaditya was gifted a new bike. He drove x km at 55 kmph.
Then he drove x+20 km at 40 kmph.
He drove his bike for 100 minutes.
How much distance did he travel?
x = 55*t --- 1
55t + 20 = 40*t1 ---- 2
t1 + t = 5/3 hr ---- 3
substituting 3 in 2
55t + 20 = 40(5/3 - t)
55t + 40t = 40*(5/3) - 20
95t = 40*(5/3) - 20
19t = 40/3 - 4 = 28/3
t = 28/(19*3) hr
Total distance travelled = (2x + 20) Km = 2*((28/57)*55) + 20 = 54.0351 + 20 = 74.0351 Km.
Ram travels a certain distance at 3km/hr and reached 15 min late. If he travels at 4 km/hr, he reached 15 min earlier.
What is the distance he has to travel.
Two buses travel to a place at 45 kmph and 60 kmph respectively. If the second bus takes 11/2 hours less than the first for the journey, then what is the length of the journey?
A man covers a distance on scooter. Had he moved 3 kmph faster he would have taken 40 min less. If he had moved 2 kmph slower he would have taken 40min more. What is the distance he wanted to cover?
The ratio between the rates of walking of A and B is 2:3 and therefore A takes 10 minute more than the time taken by B to reach the destination.
If A had walked at double the speed, how much time he would have taken to reach the destination.
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