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L.C.M of two numbers is 156 and their H.C.F is 2. If the sum of the numbers is 38, then what is their difference?

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L.C.M of two numbers is 156 and their H.C.F is 2. If the sum of the numbers is 38, then what is their difference?
posted Mar 13 by anonymous

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1 Answer

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a + b = 38
a × b = H.C.F × L.C.M = 156 × 2 = 312
(a + b )^2 - (a - b)^2 = 4ab
(a - b) = ((a + b)^2 - 4ab)^(0.5) = ((38^2) - (4 × 312))^0.5 = 14
a = 26 & b = 12.

answer Mar 13 by Tejas Naik
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