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a + b = 38
a × b = H.C.F × L.C.M = 156 × 2 = 312
(a + b )^2 - (a - b)^2 = 4ab
(a - b) = ((a + b)^2 - 4ab)^(0.5) = ((38^2) - (4 × 312))^0.5 = 14
a = 26 & b = 12.
x and y are distinct 2 digit numbers such that y is obtained by reversing the digits of x.
Suppose they also satisfy x^2 - y^2 = m^2 for some positive integer m, then find the value of x+y+m?
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