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If a^2−b^2=2640 and a^2+b^2=6338 then what is the value of 23ab?

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If a^2−b^2=2640 and a^2+b^2=6338 then what is the value of 23ab?
posted Jan 2, 2018 by anonymous

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2 Answers

+1 vote

a²−b²=2640 ___________________(i)
a²+b²=6338___________________(ii)

(i)+(ii) →
2a² = 8978
=> a = 67

(i)+(ii) →
2b² = 3698
=> b = 43


23ab = 23*67*43 = 66263

answer Jan 2, 2018 by Yasin Hossain Siinan
0 votes

66263

67*43*23

answer Jan 6, 2018 by Firstname Iskowitz
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