In a game called flip it or dip it, three people flip coins, and the odd person out has to double what others already have. After three games,each person has lost once and has thirty six pounds.

How much money did each start with?

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In a game called flip it or dip it, three people flip coins, and the odd person out has to double what others already have. After three games,each person has lost once and has thirty six pounds.

How much money did each start with?

0 votes

**58.5, 31.5 and 18 pounds**

Let initial amount be x, y and z pounds

if player with x loses first, player with y loses second and player with z loses last then we have following:

game 1 game 2 game 3 money left

(x-y-z) *2 *2 =36 (1)---> x-y-z=9

(y*2- (x-y-z)- 2z) *2 =36 (2)---> -x+3y-z=18

z*2 *2 -2*(x-y-z)- (2y-(x-y-z)-2z) =36 (3)---> -x-y+7z=36

from above we find **x=58.5 pounds, y=31.5 pounds and z=18 pounds**

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