42 views

In a game called flip it or dip it, three people flip coins, and the odd person out has to double what others already have. After three games,each person has lost once and has thirty six pounds.

posted Jul 19, 2017

58.5, 31.5 and 18 pounds

Let initial amount be x, y and z pounds
if player with x loses first, player with y loses second and player with z loses last then we have following:
game 1 game 2 game 3 money left
(x-y-z) *2 *2 =36 (1)---> x-y-z=9
(y*2- (x-y-z)- 2z) *2 =36 (2)---> -x+3y-z=18
z*2 *2 -2*(x-y-z)- (2y-(x-y-z)-2z) =36 (3)---> -x-y+7z=36
from above we find x=58.5 pounds, y=31.5 pounds and z=18 pounds

Similar Puzzles
+1 vote

Mark is throwing his son Stewart a surprise birthday party but he has limited funds.

He spent half of his money plus \$2.00 on the cake.

Half of what was left plus \$2.00 was spent on balloons and decorations.

Then he spent half of what he had left plus \$1.00 on candy.

Now he is out of money, how much did Mark start with?

Jayant went to the hardware store to buy some needed supplies. He spent half of what he had plus \$2.00 in the first store; half of what he had left plus \$1.00 in the second store; half of what he had left plus \$1.00 in the third store; and in the last store half of all he had. Three dollars were left over.

+1 vote

Grandma sent Johnny some money for his birthday. Johnny spent all of it in five stores. In each store, he spent \$1.00 more than half of what he had when he came in. How much money did he get from grandma?