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A quantity x varies inversely as the square of y. Given that x = 4 when y = 3, the value of x when y = 6?

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A quantity x varies inversely as the square of y. Given that x = 4 when y = 3, the value of x when y = 6?
posted Sep 7, 2016 by anonymous

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1 Answer

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x=k/(y*y). From given data 4=k/(3*3) gives k=36
Thus x=36/(y*y)
When y=6, x=36/(6*6) means x=1 answer

answer Dec 13, 2016 by Kewal Panesar



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