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Dual connectivity: split bearer related
The answer is 25.
A = 0 + 1 = 1
B = 1 + 3 = 4
C = 4 + 5 = 9
D = 9 + 7 = 16
E = 16 + 9 = 25
Could also be,
A = 1^2 = 1
B = 2^2 = 4
C = 3^2 = 9
D = 4^2 = 16
E = 5^2 = 25
Both give E = 25 though so it doesn't really matter how you get there
The gap between two number is odd number like 3, 5,7, 9 like that next number is 16+9=25
simple ans 25
The difference between the increments of the figures is 2 so 16 +9 = 25
A x 4 = E
B ÷ 4 = E
C + 4 = E
D - 4 = E
A + B + C + D = 100
What is the value of E ?
abcde=1 (where a,b,c,d and e are all positive real numbers)
what is the minimum value of a+b+c+d+e?
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