Ben is four times as old as his daughter.

In 20 years’ time Ben shall be twice as old as her.

How old are Ben and his daughter now?

+1 vote

Ben is four times as old as his daughter.

In 20 years’ time Ben shall be twice as old as her.

How old are Ben and his daughter now?

+1 vote

Age of **Ben** is **40** and age of his **daughter ** is **10**.

**Solution:**

Consider Ben’s age be x & his daughters age be y.

So, Ben is four times as old as his daughter.

```
x = 4y ....(1);
```

In 20 years’ time Ben shall be twice as old as her.

```
x+20 = 2(y+20) ....(2);
```

now, adding x=4y equ(1) in equ(2),

```
4y+20 = 2y+40;
4y-2y = 40-20;
2y = 20;
y = 10;
```

So, y=10 adding in equ(1)

```
x = 4(10);
x = 40;
```

+1 vote

By the given information we can form 2 equations and hence find the respective ages.

Let Ben’s age be B &

his daughters age be D.

So from the information provided we can write;

B = 4 x D &

B + 20 = 2 x (D + 20)

Substituting B value in the second equation we get.

4D + 20 = 2D + 40

2D = 20

Therefore we get the value of D as;

D = 10

Putting this value in the first equation we get;

B = 4 x D = 4 x 10 = 40′

So Ben’s age is 40

Answer is Ben’s age is 40 and his daughter’s age is 10.

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