   # Six years ago a woman was nine times the age of her niece and she is now three times the age of her ................

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Six years ago a woman was nine times the age of her niece and she is now three times the age of her niece.

What are their current ages? posted Aug 2, 2016

Woman age is 24 and niece age is 8.

Solution:
Six years ago a woman was nine times the age of her niece

f-6 = 9(n-6)

f-6 = 9n-54

f-9n = -54+6

f-9n = -48 .............(1)

she is now three times the age of her niece.

f = 3n; .................(2)

f-9n = -48

3n-9n = -48

-6n = -48

n = 48/6

n = 8

Hence, n = 8 is niece age.

And n = 8 add into (1)

f-9(8) = -48

f-72 = -48

f = -48+72

f = 24

Hence, f = 24 is woman age answer Aug 2, 2016
–1 vote

Let X be current age of aunt and Y current age of niece
Then,
X - 6 = 9 x (Y - 6) (1)
X = 3 Y (2 )
By multiplying (2) by - 1 and adding both equations:
- 6 = 9Y - 54 - 3Y,
48 = 6Y ; Y = 8 and X = 3x8 = 24 answer Aug 3, 2016 by anonymous
–1 vote

CONSIDER THE PRESENT AGE OF WOMAN AND NIECE BE X and Y
THEN GET 2 EQUATIONS IE
X=3Y AND 9(Y-6)=X-6
SOLVING GET X=24 and Y=8 which is the answer answer Aug 3, 2016

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