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Given that x+y =7 and xy=2 then x^2-y^2=?? whereas (x>y)

+1 vote
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Given that x+y =7 and xy=2 then x^2-y^2=?? whereas (x>y)
posted Jul 7, 2016 by anonymous

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1 Answer

+2 votes

7√41

x^2 - y^2 = (x+y)(x-y)
x+y=7
x-y=SQRT((x+y)^2 - 4xy)
x-y=SQRT(41)

hence
x^2 - y^2 = 7√41

answer Jul 8, 2016 by anonymous



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