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In a hotel, rooms are numbered from 101 to 550. A room is chosen at random. What is the probability that room number starts with 1, 2 or 3 and ends with 4, 5 or 6 ?
Out of which 299 room number starts with either 1, 2 or 3. (as room number 100 is not there) Now out of those 299 rooms only 90 room numbers end with 4, 5 or 6
So the probability is 90/450 i.e. 1/5 or 0.20
Total favorable ways 3c1*10c1*3c1 i.e. 3*10*3 = 90
So probability = 90/450 or 9/45
3*10*3 = 90
The probability is 90/450 i.e. 1/5 or 0.20
Where 450 are total number of room and 90 rooms starts with 1, 2 or 3 and ends with 4, 5 or 6
as rooms started from 101 to 550, it means there are 5 floors and each floor has 50 rooms.
total rooms are 250.
no. of rooms started with 1,2 &3 and ends with 4,5,6 are 75.
so, probabilty is 30%
A bag contain 5 blue and 4 black balls. Three balls are drawn at random. What is the probability that 2 are blue and 1 is black.
A bag contains 5 white, 4 red and 3 black balls. A ball is drawn at random from the bag, what is the probability that it is not black?
My house number is such that, when divided by 2, 3, 4, 5 or 6 it will always leave a remainder of 1.
However, when divided by 11 there is no remainder.
What is my house number?
I have two coins.
* One of the coin is a faulty coin having tail on both side of it.
* The other coin is a perfect coin (heads on side and tail on other).
I blind fold myself and pick a coin and put the coin on table. The face of coin towards the sky is tail.
What is the probability that other side is also tail ?
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